2x^2=243

Solution for 2x^2=243 equation:

2x^2=243

We move all terms to the left:

2x^2-(243)=0

a = 2; b = 0; c = -243;
Δ = b2-4ac
Δ = 02-4·2·(-243)
Δ = 1944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1944}=\sqrt{324*6}=\sqrt{324}*\sqrt{6}=18\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{6}}{2*2}=\frac{0-18\sqrt{6}}{4}
=-\frac{18\sqrt{6}}{4}
=-\frac{9\sqrt{6}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{6}}{2*2}=\frac{0+18\sqrt{6}}{4}
=\frac{18\sqrt{6}}{4}
=\frac{9\sqrt{6}}{2}
$